FUNCTION FC53: VOID // MAN CUT MODE SUB FUNCTION 513 TO 412 //
VAR_TEMP
Y1 : INT;
Y2 : INT;
Y3 : INT;
I_FOR : INT;
END_VAR
VAR_INPUT
X1, X2, X3, X4 : INT; // X1:out LLOOP; X2:out SLOOP; X3:in LLOOP; X4:in SLOOP; //
END_VAR
Y1:= DB30.WANT_CUT_NUM;
Y2:=X1+Y1-1;
IF Y2>5 THEN Y2:=Y2-5; END_IF;
IF DB30.STATE=5 AND DB30.LLOOP=Y2 AND DB30.SLOOP=X2 AND DB30.V513_V412=TRUE THEN//CUT OUT
FOR I_FOR:=1 TO 30 BY 1 DO
DB30.VALVES_TEMP2[I_FOR] :=FALSE;
END_FOR;
DB30.LLOOP :=X3; DB30.SLOOP :=X4; //CUT IN
DB30.V513_V412:=FALSE; DB30.V412_V513:=FALSE;
DB30.STATE:=4;
DB30.V412:=TRUE;
DB30.V513:=FALSE;
DB30.V513_V412:=FALSE;
DB30.CUTTED_NUM:=DB30.WANT_CUT_NUM;
DB30.WANT_CUT_NUM:=0;
M61.0:=0;
END_IF;
END_FUNCTION
其中的： FOR I_FOR:=1 TO 30 BY 1 DO
DB30.VALVES_TEMP2[I_FOR] :=FALSE;
END_FOR;
这个循环语句是什么意思啊，C中有学过，忘记了，好像还有点不一样呢，大哥大嫂，给俺讲讲吧
最佳答案
和前一个问题一样，这个循环就是将数组中的30个位（DB30.VALVES_TEMP2[1]~DB30.VALVES_TEMP2[30])清0用的
提问者对于答案的评价：
TS
原创文章，作者：more0621，如若转载，请注明出处：https://www.zhaoplc.com/plc302852.html
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